How do you solve for y in terms of x?

If you graph the function given by the equation you can find the x- intercepts by solving the equation for x. From the graph you can observe that the graph is fairly flat between the two x-intercepts, at around -1 and -1.576. You can find the value of y at these two points by plugging in each value of x and solving the equation. The answer is -0.923 and -0.923. Thus, the equation

How do you solve for y in terms of u?

There are several ways to solve for y in terms of u. The simplest is to plug it in directly. If we know that and in terms of and we can plug those expressions for and into the equation for and solve for directly. This is a little more complicated if the two variables are in different forms—for example, if is in terms of while is in terms of We can solve this using other techniques.

How do you solve for y in terms of s?

If the two sides of the equation represent two sides of a triangle, then you can solve for the missing length in terms of the sides you know. In this case, the two sides of the triangle would be the length of a line segment that connects the two known points.

How do you solve for y when x=

You can use the fact that the line is a tangent to the circle to solve for either variable. You could take the derivative of the circle equation with respect to x to find the slope of the line at the point. Once you have the slope, you can solve for circumference or area to find the value of y.

How do you solve for y in terms of p?

You can use the inverse of the function ƒ(x) = p to solve for p, so that ƒ(y) = x if the function is bijective. In order for this to work, however, you need to check that ƒ(x) is one-to-one and onto. If it is, then the function ƒ(y) = p is also one-to-one and onto, thus solving the equation ƒ