How to multiply fractions with square roots in the denominator?

When multiplying two fraction with square roots in the denominator, you need to multiply the numerator of the first fraction by the denominator of the second fraction and the result will be the answer. In such a case, you need to make sure that the roots are in the denominator, so, if you have a fraction in which the denominator has a square root, you'll need to multiply the numerator by the square root of the denominator as well.

How is a fraction with square roots in the

One way to solve a fraction with square roots in the denominator is to multiply the top and the bottom of the fraction by its conjugate. The conjugate of a fraction is the fraction whose numerator is the product of the denominator and the square root of its denominator. For example: If you want to find the value of you can multiply both the top and the bottom by the conjugate of the denominator, which is to get If

How

It's not that multiplying by a fraction is hard – it's just a little different than multiplying by a whole number. When you multiply two fractions you want to multiply the fraction in the denominator with the fraction in the numerator. So, for example, if you have 4/3 × 5/2, you want to multiply 4/3 by 5/2 to get 20/6. If you have 15/8 × 3/4, you want to multiply 15/8 by 3

How to multiply fractions with square roots in the denominator by a prime number?

When multiplying a fraction with a square root in the denominator by a prime number, you can use the cross-multiplication method. First, change the fraction to have a denominator that equals the prime number. For example, to multiply by you would divide by to get Now find the least common denominator as you did before--the product of the two denominators in your original fraction. This number will be the denominator of the fraction you are multiplying.

How do you solve a fraction with square roots in the denominator?

One place you’ll run into these when solving word problems is when you need to find the value of a missing area. For example, if you have a circle with a diameter of 6 feet, that’s the same as a square with sides of length 6. This is a pretty common problem, especially when you’re working with a circle.